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archive_info: use timelocal correctly

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Because we always have 4-digit years, we can simply pass
the year itself to timelocal instead of subtracting 1900.
Like this it will also work for years not in the range 2000-2999.

See also:
https://perldoc.perl.org/Time/Local.html#Year-Value-Interpretation

Signed-off-by: Fabian Ebner <f.ebner@proxmox.com>
This commit is contained in:
Fabian Ebner
2020-07-08 10:22:19 +02:00
committed by Thomas Lamprecht
parent e0bbbb6f48
commit b1ddc54a93
2 changed files with 31 additions and 1 deletions
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2
PVE/Storage.pm
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@ -1404,7 +1404,7 @@ sub archive_info {
if ($volid =~ /^(vzdump-${type}-([1-9][0-9]{2,8})-(\d{4})_(\d{2})_(\d{2})-(\d{2})_(\d{2})_(\d{2}))\.${format_re}$/) {
$info->{logfilename} = "$1.log";
$info->{vmid} = int($2);
$info->{ctime} = timelocal($8, $7, $6, $5, $4 - 1, $3 - 1900);
$info->{ctime} = timelocal($8, $7, $6, $5, $4 - 1, $3);
$info->{is_std_name} = 1;
} else {
$info->{is_std_name} = 0;